4(x^2+1)=3(x^2-1)

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Solution for 4(x^2+1)=3(x^2-1) equation: 



4(x^2+1)=3(x^2-1)

We move all terms to the left:

4(x^2+1)-(3(x^2-1))=0

We multiply parentheses

4x^2-(3(x^2-1))+4=0



We calculate terms in parentheses: -(3(x^2-1)), so:

3(x^2-1)

We multiply parentheses

3x^2-3

Back to the equation:

-(3x^2-3)



We get rid of parentheses

4x^2-3x^2+3+4=0

We add all the numbers together, and all the variables

x^2+7=0

a = 1; b = 0; c = +7;
Δ = b2-4ac
Δ = 02-4·1·7
Δ = -28
Delta is less than zero, so there is no solution for the equation

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